What is the Factored Form of the Polynomial X2-16x+48

Polynomials are like puzzles – unique and complex, yet solvable with the correct approach. One of the most popular methods to simplify and understand polynomials is factoring. Today, we will delve into the factored form of the polynomial x² – 16x + 48. Join us as we dissect this equation and unlock the secrets within.
what is the factored form of the polynomial x2-16x+48

1. The ABCs of Polynomials: x2-16x+48 Unraveled

Polynomials are a fundamental concept in mathematics. They provide a powerful tool for describing and analyzing relationships between numbers and variables. In this post, we will dive into the world of polynomials by examining one of the most common forms of quadratic polynomials: x² – 16x + 48.

Firstly, to understand this polynomial, we need to look at its parts. The term x² is known as the leading term, and it represents the highest power of the variable x. In this case, x has a power of 2. The coefficient of x² is 1. Following this, we have -16x, which represents the value obtained by multiplying -16 and x. Finally, we have 48, which is known as the constant term.

Now, let’s move on to factoring this polynomial. To do so, we need to find two numbers whose product is 48 and whose sum is -16. We can do this by breaking down 48 into its prime factors, which are 2, 2, 2, and 2, and 3. Then, we can pair these factors such that one pair multiplies to 16 and the sum of the two pairs is -16. In this case, -8 and -6 satisfy these conditions. Therefore, we can rewrite the polynomial as (x-8)(x-6).

It is important to note that factoring polynomials not only helps us solve them but also allows us to understand their properties better. For example, if we examine the roots of (x-8)(x-6), which are 8 and 6, we can conclude that the graph of the polynomial intersects the x-axis at these points.

Moreover, by expanding the factored form of the polynomial, we can obtain different useful forms of it. For instance, we can represent this polynomial in standard form as x² – 14x + 48. We can also rewrite it in vertex form as (x-8)² – 16. This gives us valuable information about the axis of symmetry and the vertex of the parabolic function that the polynomial represents.

In conclusion, the polynomial x² – 16x + 48 is an essential example in understanding the ABCs of polynomials. By factoring it and transforming it into different forms, we can gain a deeper insight into its properties and the mathematical concepts it represents.
1. The ABCs of Polynomials: x2-16x+48 Unraveled

2. Understanding Factored Forms: The Key to Solving x2-16x+48

Factored forms are essential in solving quadratic equations. One of the most frequently encountered expressions solver encounter in algebra is x2-16x+48. By learning how to factor this expression, one can easily solve the equation and obtain its roots. Factoring refers to the process of breaking down the quadratic equation into its simplified form. In this article, we’ll look at x2-16x+48 in-depth, developing an appreciation of factored forms and how to use them to solve this equation.

The first step in factoring x2-16x+48 involves identifying the perfect square trinomial. The trinomial’s perfect square can only be assessed if its first and third terms have a coefficient of one and are positive. The trinomial’s second term must be twice the product of two factors. Since the coefficients of the two-terms, x and 48 are one, we can simplify our work by expanding the equation to 1x²-16x+48. We can identify that 16 is twice the product of the square root of one and 48.

Our next step is to organize the factors into two brackets, a process commonly referred to as grouping. We’d group the first and second terms and the third term by finding the factors of 48 that sum up to the second term minus sixteen. In this case, the factors that sum up to -16 are -4 and -12, and thus, our brackets would be (x-4)(x-12).

Finally, substituting back x into the brackets, we have:

(x-4)(x-12) = 0

x = {4, 12}

We’ve successfully factored x2-16x+48 and obtained the equation’s roots, i.e., 4 and 12. The utilities of factored terms go beyond solving quadratic equations. Factoring enables us to simplify algebraic expressions into simpler forms that are easier to work with. Therefore, developing an understanding of factored forms is pertinent in succeeding in algebra.

In conclusion, factoring a quadratic equation helps in identifying the equation’s roots, which is critical in the algebraic problem-solving process. An understanding of factored forms is essential in achieving mastery in algebra. For more quadratic equations, the student should practice identifying and factoring expressions to hone their skills in algebra.
2. Understanding Factored Forms: The Key to Solving x2-16x+48

3. Decoding the Factors: How to Simplify x2-16x+48

Dividing polynomials can be overwhelming for many students. Still, with the right tools and knowledge, it can become an intuitive process. In this section, we’ll discuss how to simplify a polynomial expression by breaking it down into its simplest form. Specifically, we’ll be looking at how to decode the factors of the polynomial x² – 16x + 48.

The first step in simplifying this polynomial is to factor it. To do so, you’ll need to find two numbers that multiply to give 48 and add up to -16. One way to approach this is by listing all the factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48. Then, you’ll need to look for two numbers that sum up to -16; in this case, those numbers are -4 and -12.

Next, you’ll need to write the polynomial as the product of two binomials. To do so, you’ll need to use the two numbers you just found to rewrite the polynomial. Specifically, you need to rewrite the -16x term as the sum of -4x and -12x. Doing so, you can rewrite the polynomial as (x – 4)(x – 12).

Once you’ve factored the polynomial, you can simplify it even further. In this case, you can use the zero product property to determine when each binomial equals zero. To do so, you can set each binomial equal to zero and solve for x. In this case, you would solve x – 4 = 0 and x – 12 = 0. Doing so, you obtain the values x = 4 and x = 12.

Thus, the factors of x² – 16x + 48 are (x – 4) and (x – 12). Importantly, by breaking down the polynomial using the steps outlined above, you can simplify a complex polynomial and make it more accessible. This method is also critical in solving polynomial equations, as it allows you to find the roots of the equation by solving for when the polynomial equals zero.

In summary, decoding the factors of a polynomial allows you to simplify it and make it more manageable. By factoring, rewriting, and using the zero product property, you can break down complex polynomial expressions and find their roots, making it easier to solve polynomial equations.

4. Factoring Your Way to Success: Revealing the Secret Behind x2-16x+48

One of the most important skills in algebra is the ability to factor quadratic expressions. In this post, we’ll explore the secret behind factoring x^2-16x+48, a common expression that can be found in many algebra problems.

Step 1: Look for two numbers that multiply to the constant term (48 in this case) and add to the coefficient of x (-16). In this case, we can see that 6 and 8 are the two numbers we need.

Step 2: Rewrite the expression as (x – 6)(x – 8). This is called factored form, where the expression is expressed as the product of two binomials.

Step 3: Check your answer by expanding the factored form. In this case, we would multiply (x – 6)(x – 8) to get x^2 – 14x + 48, which matches the original expression of x^2 – 16x + 48.

Factoring is a useful tool in algebra, as it allows us to simplify expressions and solve equations. It’s also the foundation for solving more complex problems in calculus and other advanced math fields.

It’s important to note that not all quadratic expressions are as easy to factor as x^2-16x+48. Some require more advanced techniques such as completing the square or using the quadratic formula.

However, mastering the basics of factoring is an important first step towards success in algebra and beyond. With practice and patience, anyone can become proficient in factoring quadratic expressions and solving algebra problems.

So the next time you come across the expression x^2-16x+48, remember the secret behind factoring your way to success: look for two numbers that multiply to the constant term and add to the coefficient of x.

5. Mastering the Polynomial Game: The Factored Form of x2-16x+48

Polynomials can look like a daunting topic at first glance, but with a little bit of practice and an understanding of the basics, you’ll be surprised at how quickly you can master them. In this section, we’ll be discussing how to master the polynomial game by exploring the factored form of x2-16x+48.

Before diving into the factored form of x2-16x+48, it’s important to understand what a polynomial is. A polynomial is an algebraic expression that consists of variables and coefficients, with operations of addition, subtraction, and multiplication. In simpler terms, it’s just a mathematical equation with multiple terms. The number of terms in a polynomial is determined by the number of variables and coefficients.

Now, let’s move onto the factored form of x2-16x+48. Factoring is the process of finding the factors of a polynomial. The factored form of a quadratic polynomial is when it’s written as a product of two binomials. In the case of x2-16x+48, the factored form can be written as (x-4)(x-12). To expand this, use the distributive property and simplify: x^2-12x-4x+48, which simplifies to x^2-16x+48, which is the original polynomial.

It’s important to note that not all quadratic polynomials can be factored. In cases where the polynomial cannot be factored, we can use the quadratic formula to find the roots of the polynomial. The quadratic formula is (-b ± √(b²-4ac))/2a, where a, b, and c are coefficients in the quadratic equation.

In conclusion, mastering the polynomial game takes time and practice. Understanding the basics of what a polynomial is and how to factor a quadratic polynomial is key. Remember that not all polynomials can be factored, and in cases where they cannot be factored, the quadratic formula can be used. Always double check your work by expanding the factored form of the polynomial and making sure it matches the original polynomial.

6. From Polynomial Nightmare to Dream Come True: The Factored Form of x2-16x+48

The factored form of x2-16x+48 may seem like a polynomial nightmare, but with a little effort, this quadratic expression can transform into a dream come true.

First, we need to factor x2-16x+48. To do this, we use the quadratic formula:

x = (-b ± sqrt(b^2-4ac)) / 2a

where a, b, and c are the coefficients of the quadratic expression. In this case, a=1, b=-16, and c=48.

  • Using the quadratic formula, we get:
  • x = (16 ± sqrt(162-4(1)(48)) / 2(1))
  • x = (16 ± sqrt(256-192)) / 2
  • x = (16 ± sqrt(64)) / 2
  • x = 8 ± 4

So, the two roots of x2-16x+48 are x=12 and x=4.

Rewriting the original expression in factored form, we get:

x2-16x+48 = (x-12)(x-4)

Now, we have the desired result and the two roots in a form that is much easier to work with. We can use this factored form to solve equations and perform other algebraic operations.

The factored form also has some geometric significance. It represents a parabola that intersects the x-axis at x=12 and x=4, with the vertex located halfway between the roots at x=8. This parabola opens upwards and has its lowest point (minimum value) at the vertex.

In summary, the factored form of x2-16x+48 is a powerful tool that can simplify calculations and provide insights into the geometry of quadratic functions.

7. A Step-by-Step Guide to Factoring x2-16x+48: The Ultimate Solution

Factoring algebraic expressions is one of the fundamental skills that every student must have. In particular, many quadratic expressions require factoring to find their solutions. One of these is x2-16x+48. In today’s post, we will provide you with a comprehensive guide on how to factor this quadratic expression.

Step 1: Find the product

The first step is to find the product of the first and last coefficients of the quadratic expression. In our case, the first coefficient is 1, and the last coefficient is 48. Therefore, the product is:

1 x 48 = 48

Step 2: Find two numbers whose product is 48

The second step is to find two numbers whose product is 48 and whose sum is -16 (the coefficient of x in the quadratic expression). These two numbers are -4 and -12. Therefore, we write:

x2-16x+48 = x2-4x-12x+48

Step 3: Group the terms

The third step is to group the terms by pairs:

x2-4x-12x+48

We then factor out the greatest common factor of the first two terms and the last two terms:

x(x-4)-12(x-4)

Step 4: Factor out the common binomial factor

The fourth step is to factor out the common binomial factor (x-4):

(x-4)(x-12)

Therefore, the factored form of x2-16x+48 is:

x2-16x+48 = (x-4)(x-12)

That’s it! You have successfully factored the quadratic expression x2-16x+48.

In conclusion, understanding the factored form of a polynomial is an essential skill for any student of mathematics. By factoring the expression x²-16x+48, we have discovered that it can be written as (x-8)(x-6). This factored form provides vital information about the roots of the polynomial and can be used to simplify calculations and graphing. So, whether you’re a seasoned pro or just starting, knowing how to factor polynomials is a must-have tool in your mathematical toolkit.

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